四小时测试你的Sql能力—MySQL经典练习50题Think-Yang-

1 简介

Sql能力是开发人员的业务能力之根，平常习惯了CRUD，可不要忘了回归根本哦！

2 初始环境

2.1 表结构

–1.学生表
Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别
–2.课程表
Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号
–3.教师表
Teacher(t_id,t_name) –教师编号,教师姓名
–4.成绩表
Score(s_id,c_id,s_score) –学生编号,课程编号,分数

2.2 初始化Sql

• 建表

 --学生表 CREATE TABLE `Student`( `s_id` VARCHAR(20), `s_name` VARCHAR(20) NOT NULL DEFAULT '', `s_birth` VARCHAR(20) NOT NULL DEFAULT '', `s_sex` VARCHAR(10) NOT NULL DEFAULT '', PRIMARY KEY(`s_id`) ); --课程表 CREATE TABLE `Course`( `c_id` VARCHAR(20), `c_name` VARCHAR(20) NOT NULL DEFAULT '', `t_id` VARCHAR(20) NOT NULL, PRIMARY KEY(`c_id`) ); --教师表 CREATE TABLE `Teacher`( `t_id` VARCHAR(20), `t_name` VARCHAR(20) NOT NULL DEFAULT '', PRIMARY KEY(`t_id`) ); --成绩表 CREATE TABLE `Score`( `s_id` VARCHAR(20), `c_id` VARCHAR(20), `s_score` INT(3), PRIMARY KEY(`s_id`,`c_id`) ); 

• 插入学生表测试数据

 insert into Student values('01' , '赵雷' , '1990-01-01' , '男'); insert into Student values('02' , '钱电' , '1990-12-21' , '男'); insert into Student values('03' , '孙风' , '1990-05-20' , '男'); insert into Student values('04' , '李云' , '1990-08-06' , '男'); insert into Student values('05' , '周梅' , '1991-12-01' , '女'); insert into Student values('06' , '吴兰' , '1992-03-01' , '女'); insert into Student values('07' , '郑竹' , '1989-07-01' , '女'); insert into Student values('08' , '王菊' , '1990-01-20' , '女'); --课程表测试数据 insert into Course values('01' , '语文' , '02'); insert into Course values('02' , '数学' , '01'); insert into Course values('03' , '英语' , '03'); --教师表测试数据 insert into Teacher values('01' , '张三'); insert into Teacher values('02' , '李四'); insert into Teacher values('03' , '王五'); --成绩表测试数据 insert into Score values('01' , '01' , 80); insert into Score values('01' , '02' , 90); insert into Score values('01' , '03' , 99); insert into Score values('02' , '01' , 70); insert into Score values('02' , '02' , 60); insert into Score values('02' , '03' , 80); insert into Score values('03' , '01' , 80); insert into Score values('03' , '02' , 80); insert into Score values('03' , '03' , 80); insert into Score values('04' , '01' , 50); insert into Score values('04' , '02' , 30); insert into Score values('04' , '03' , 20); insert into Score values('05' , '01' , 76); insert into Score values('05' , '02' , 87); insert into Score values('06' , '01' , 31); insert into Score values('06' , '03' , 34); insert into Score values('07' , '02' , 89); insert into Score values('07' , '03' , 98); 

3 试卷

-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数  -- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数 -- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩 -- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩 (包括有成绩的和无成绩的) -- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩 -- 6、查询"李"姓老师的数量  -- 7、查询学过"张三"老师授课的同学的信息  -- 8、查询没学过"张三"老师授课的同学的信息  -- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息 -- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息 -- 11、查询没有学全所有课程的同学的信息 -- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 -- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 -- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名 -- 15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩 -- 16、检索"01"课程分数小于60，按分数降序排列的学生信息 -- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩 -- 18.查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率 (及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90) -- 19、按各科成绩进行排序，并显示排名(实现不完全) -- 20、查询学生的总成绩并进行排名 -- 21、查询不同老师所教不同课程平均分从高到低显示  -- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩 -- 23、统计各科成绩各分数段人数：课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比 -- 24、查询学生平均成绩及其名次  -- 25、查询各科成绩前三名的记录 -- 26、查询每门课程被选修的学生数  -- 27、查询出只有两门课程的全部学生的学号和姓名 -- 28、查询男生、女生人数 -- 29、查询名字中含有"风"字的学生信息 -- 30、查询同名同性学生名单，并统计同名人数  -- 31、查询1990年出生的学生名单 -- 32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列  -- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 -- 34、查询课程名称为"数学"，且分数低于60的学生姓名和分数  -- 35、查询所有学生的课程及分数情况； -- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数 -- 37、查询不及格的课程 -- 38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名 -- 39、求每门课程的学生人数 -- 40、查询选修"张三"老师所授课程的学生中，成绩最高的学生信息及其成绩  -- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩  -- 42、查询每门功成绩最好的前两名  -- 43、统计每门课程的学生选修人数（超过5人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，(若人数相同，按课程号升序排列) -- 44、检索至少选修两门课程的学生学号  -- 45、查询选修了全部课程的学生信息 -- 46、查询各学生的年龄 -- 47、查询本周过生日的学生 -- 48、查询下周过生日的学生 -- 49、查询本月过生日的学生 -- 50、查询下月过生日的学生 

4 参考答案

1、查询”01″课程比”02″课程成绩高的学生的信息及课程分数

select st.*,sc.s_score as '语文' ,sc2.s_score '数学' from student st left join score sc on sc.s_id=st.s_id and sc.c_id='01' left join score sc2 on sc2.s_id=st.s_id and sc2.c_id='02' where sc.s_score>sc2.s_score 

2、查询”01″课程比”02″课程成绩低的学生的信息及课程分数

select st.*,sc.s_score '语文',sc2.s_score '数学' from student st left join score sc on sc.s_id=st.s_id and sc.c_id='01' left join score sc2 on sc2.s_id=st.s_id and sc2.c_id='02' where sc.s_score<sc2.s_score 

3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩

select st.s_id,st.s_name,ROUND(AVG(sc.s_score),2) "平均成绩" from student st left join score sc on sc.s_id=st.s_id group by st.s_id having AVG(sc.s_score)>=60 

4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩((包括有成绩的和无成绩的))

select st.s_id,st.s_name,(case when ROUND(AVG(sc.s_score),2) is null then 0 else ROUND(AVG(sc.s_score),2) end ) "平均成绩" from student st left join score sc on sc.s_id=st.s_id group by st.s_id having AVG(sc.s_score)<60 or AVG(sc.s_score) is NULL 

5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩

select st.s_id,st.s_name,count(sc.c_id) "选课总数",sum(case when sc.s_score is null then 0 else sc.s_score end) "总成绩" from student st  left join score sc on st.s_id = sc.s_id  group by st.s_id 

6、查询”李”姓老师的数量

select t.t_name,count(t.t_id) from teacher t group by t.t_id having t.t_name like "李%"; 

7、查询学过”张三”老师授课的同学的信息

select st.* from student st  left join score sc on sc.s_id=st.s_id left join course c on c.c_id=sc.c_id left join teacher t on t.t_id=c.t_id  where t.t_name="张三" 

8、查询没学过”张三”老师授课的同学的信息

select c.* from course c left join teacher t on t.t_id=c.t_id where  t.t_name="张三" -- 有张三老师课成绩的st.s_id select sc.s_id from score sc where sc.c_id in (select c.c_id from course c left join teacher t on t.t_id=c.t_id where  t.t_name="张三") -- 不在上面查到的st.s_id的学生信息,即没学过张三老师授课的同学信息 select st.* from student st where st.s_id not in( select sc.s_id from score sc where sc.c_id in (select c.c_id from course c left join teacher t on t.t_id=c.t_id where  t.t_name="张三") ) 

9、查询学过编号为”01″并且也学过编号为”02″的课程的同学的信息

select st.* from student st  inner join score sc on sc.s_id = st.s_id inner join course c on c.c_id=sc.c_id and c.c_id="01" where st.s_id in ( select st2.s_id from student st2  inner join score sc2 on sc2.s_id = st2.s_id inner join course c2 on c2.c_id=sc2.c_id and c2.c_id="02" ) 

10、查询学过编号为”01″但是没有学过编号为”02″的课程的同学的信息

select st.* from student st  inner join score sc on sc.s_id = st.s_id inner join course c on c.c_id=sc.c_id and c.c_id="01" where st.s_id not in ( select st2.s_id from student st2  inner join score sc2 on sc2.s_id = st2.s_id inner join course c2 on c2.c_id=sc2.c_id and c2.c_id="02" ) 

11、查询没有学全所有课程的同学的信息

select * from student where s_id not in ( select st.s_id from student st  inner join score sc on sc.s_id = st.s_id and sc.c_id="01" where st.s_id  in ( select st1.s_id from student st1  inner join score sc2 on sc2.s_id = st1.s_id and sc2.c_id="02" ) and st.s_id in ( select st2.s_id from student st2  inner join score sc2 on sc2.s_id = st2.s_id and sc2.c_id="03" )) 

12、查询至少有一门课与学号为”01″的同学所学相同的同学的信息

select distinct st.* from student st  left join score sc on sc.s_id=st.s_id where sc.c_id in ( select sc2.c_id from student st2 left join score sc2 on sc2.s_id=st2.s_id where st2.s_id ='01' ) 

13、查询和”01″号的同学学习的课程完全相同的其他同学的信息

select  st.* from student st  left join score sc on sc.s_id=st.s_id group by st.s_id having group_concat(sc.c_id) = ( select  group_concat(sc2.c_id) from student st2 left join score sc2 on sc2.s_id=st2.s_id where st2.s_id ='01' ) 

14、查询没学过”张三”老师讲授的任一门课程的学生姓名

select st.s_name from student st  where st.s_id not in ( select sc.s_id from score sc  inner join course c on c.c_id=sc.c_id inner join teacher t on t.t_id=c.t_id and t.t_name="张三" ) 

15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩

select st.s_id,st.s_name,avg(sc.s_score) from student st left join score sc on sc.s_id=st.s_id where sc.s_id in ( select sc.s_id from score sc  where sc.s_score<60 or sc.s_score is NULL group by sc.s_id having COUNT(1)>=2 ) group by st.s_id 

16、检索”01″课程分数小于60，按分数降序排列的学生信息

select st.*,sc.s_score from student st  inner join score sc on sc.s_id=st.s_id and sc.c_id="01" and sc.s_score<60 order by sc.s_score desc 

17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

select st.s_id,st.s_name,avg(sc4.s_score) "平均分",sc.s_score "语文",sc2.s_score "数学",sc3.s_score "英语" from student st left join score sc  on sc.s_id=st.s_id  and sc.c_id="01" left join score sc2 on sc2.s_id=st.s_id and sc2.c_id="02" left join score sc3 on sc3.s_id=st.s_id and sc3.c_id="03" left join score sc4 on sc4.s_id=st.s_id group by st.s_id  order by avg(sc4.s_score) desc 

18.查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率(及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90)

select c.c_id,c.c_name,max(sc.s_score) "最高分",MIN(sc2.s_score) "最低分",avg(sc3.s_score) "平均分" ,((select count(s_id) from score where s_score>=60 and c_id=c.c_id )/(select count(s_id) from score where c_id=c.c_id)) "及格率" ,((select count(s_id) from score where s_score>=70 and s_score<80 and c_id=c.c_id )/(select count(s_id) from score where c_id=c.c_id)) "中等率" ,((select count(s_id) from score where s_score>=80 and s_score<90 and c_id=c.c_id )/(select count(s_id) from score where c_id=c.c_id)) "优良率" ,((select count(s_id) from score where s_score>=90 and c_id=c.c_id )/(select count(s_id) from score where c_id=c.c_id)) "优秀率" from course c left join score sc on sc.c_id=c.c_id  left join score sc2 on sc2.c_id=c.c_id  left join score sc3 on sc3.c_id=c.c_id  group by c.c_id 

19、按各科成绩进行排序，并显示排名

select c1.s_id,c1.c_id,c1.c_name,@score:=c1.s_score,@i:=@i+1 from (select c.c_name,sc.* from course c  left join score sc on sc.c_id=c.c_id where c.c_id="01" order by sc.s_score desc) c1 , (select @i:=0) a union all select c2.s_id,c2.c_id,c2.c_name,c2.s_score,@ii:=@ii+1 from (select c.c_name,sc.* from course c  left join score sc on sc.c_id=c.c_id where c.c_id="02" order by sc.s_score desc) c2 , (select @ii:=0) aa  union all select c3.s_id,c3.c_id,c3.c_name,c3.s_score,@iii:=@iii+1 from (select c.c_name,sc.* from course c  left join score sc on sc.c_id=c.c_id where c.c_id="03" order by sc.s_score desc) c3; set @iii=0; 

20、查询学生的总成绩并进行排名

select st.s_id,st.s_name ,(case when sum(sc.s_score) is null then 0 else sum(sc.s_score) end) from student st left join score sc on sc.s_id=st.s_id group by st.s_id order by sum(sc.s_score) desc 

21、查询不同老师所教不同课程平均分从高到低显示

select t.t_id,t.t_name,c.c_name,avg(sc.s_score) from teacher t  left join course c on c.t_id=t.t_id  left join score sc on sc.c_id =c.c_id group by t.t_id order by avg(sc.s_score) desc 

22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

select a.* from ( select st.*,c.c_id,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id =sc.c_id and c.c_id="01" order by sc.s_score desc LIMIT 1,2 ) a union all select b.* from ( select st.*,c.c_id,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id =sc.c_id and c.c_id="02" order by sc.s_score desc LIMIT 1,2) b union all select c.* from ( select st.*,c.c_id,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id =sc.c_id and c.c_id="03" order by sc.s_score desc LIMIT 1,2) c 

23、统计各科成绩各分数段人数：课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比

select c.c_id,c.c_name  ,((select count(1) from score sc where sc.c_id=c.c_id and sc.s_score<=100 and sc.s_score>80)/(select count(1) from score sc where sc.c_id=c.c_id )) "100-85" ,((select count(1) from score sc where sc.c_id=c.c_id and sc.s_score<=85 and sc.s_score>70)/(select count(1) from score sc where sc.c_id=c.c_id )) "85-70" ,((select count(1) from score sc where sc.c_id=c.c_id and sc.s_score<=70 and sc.s_score>60)/(select count(1) from score sc where sc.c_id=c.c_id )) "70-60" ,((select count(1) from score sc where sc.c_id=c.c_id and sc.s_score<=60 and sc.s_score>=0)/(select count(1) from score sc where sc.c_id=c.c_id )) "60-0" from course c order by c.c_id 

24、查询学生平均成绩及其名次

set @i=0; select a.*,@i:=@i+1 from ( select st.s_id,st.s_name,round((case when avg(sc.s_score) is null then 0 else avg(sc.s_score) end),2) "平均分" from student st left join score sc on sc.s_id=st.s_id group by st.s_id order by sc.s_score desc) a 

25、查询各科成绩前三名的记录

select a.* from ( select st.s_id,st.s_name,c.c_id,c.c_name,sc.s_score from student st  left join score sc on sc.s_id=st.s_id  inner join course c on c.c_id=sc.c_id and c.c_id='01' order by sc.s_score desc LIMIT 0,3) a union all select b.* from ( select st.s_id,st.s_name,c.c_id,c.c_name,sc.s_score from student st  left join score sc on sc.s_id=st.s_id  inner join course c on c.c_id=sc.c_id and c.c_id='02' order by sc.s_score desc LIMIT 0,3) b union all select c.* from ( select st.s_id,st.s_name,c.c_id,c.c_name,sc.s_score from student st  left join score sc on sc.s_id=st.s_id  inner join course c on c.c_id=sc.c_id and c.c_id='03' order by sc.s_score desc LIMIT 0,3) c 

26、查询每门课程被选修的学生数

select c.c_id,c.c_name,count(1) from course c  left join score sc on sc.c_id=c.c_id inner join student st on st.s_id=c.c_id group by st.s_id 

27、查询出只有两门课程的全部学生的学号和姓名

select st.s_id,st.s_name from student st  left join score sc on sc.s_id=st.s_id inner join course c on c.c_id=sc.c_id  group by st.s_id having count(1)=2 

28、查询男生、女生人数

select st.s_sex,count(1) from student st group by st.s_sex 

29、查询名字中含有”风”字的学生信息

select st.* from student st where st.s_name like "%风%"; 

30、查询同名同性学生名单，并统计同名人数

select st.*,count(1) from student st group by st.s_name,st.s_sex having count(1)>1 

31、查询1990年出生的学生名单

select st.* from student st where st.s_birth like "1990%"; 

32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列

select c.c_id,c.c_name,avg(sc.s_score) from course c inner join score sc on sc.c_id=c.c_id   group by c.c_id order by avg(sc.s_score) desc,c.c_id asc 

33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

select st.s_id,st.s_name,avg(sc.s_score) from student st left join score sc on sc.s_id=st.s_id group by st.s_id having avg(sc.s_score)>=85 

34、查询课程名称为”数学”，且分数低于60的学生姓名和分数

select st.s_id,st.s_name,sc.s_score from student st inner join score sc on sc.s_id=st.s_id and sc.s_score<60 inner join course c on c.c_id=sc.c_id and c.c_name ="数学" 

35、查询所有学生的课程及分数情况；

select st.s_id,st.s_name,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id left join course c on c.c_id =sc.c_id order by st.s_id,c.c_name 

36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数

select st2.s_id,st2.s_name,c2.c_name,sc2.s_score from student st2 left join score sc2 on sc2.s_id=st2.s_id left join course c2 on c2.c_id=sc2.c_id  where st2.s_id in( select st.s_id from student st  left join score sc on sc.s_id=st.s_id  group by st.s_id having min(sc.s_score)>=70) order by s_id 

37、查询不及格的课程

select st.s_id,c.c_name,st.s_name,sc.s_score from student st inner join score sc on sc.s_id=st.s_id and  sc.s_score<60 inner join course c on c.c_id=sc.c_id  

38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名

select st.s_id,st.s_name,sc.s_score from student st inner join score sc on sc.s_id=st.s_id and sc.c_id="01" and sc.s_score>=80 

39、求每门课程的学生人数

select c.c_id,c.c_name,count(1) from course c inner join score sc on sc.c_id=c.c_id group by c.c_id 

40、查询选修”张三”老师所授课程的学生中，成绩最高的学生信息及其成绩

select st.*,c.c_name,sc.s_score,t.t_name from student st inner join score sc on sc.s_id=st.s_id inner join course c on c.c_id=sc.c_id  inner join teacher t on t.t_id=c.t_id and  t.t_name="张三" order by sc.s_score desc limit 0,1 

41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩

select st.s_id,st.s_name,sc.c_id,sc.s_score from student st  left join score sc on sc.s_id=st.s_id left join course c on c.c_id=sc.c_id where ( select count(1) from student st2  left join score sc2 on sc2.s_id=st2.s_id left join course c2 on c2.c_id=sc2.c_id where sc.s_score=sc2.s_score and c.c_id!=c2.c_id  )>1 

42、查询每门功成绩最好的前两名

select a.* from (select st.s_id,st.s_name,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id=sc.c_id and c.c_id="01" order by sc.s_score desc limit 0,2) a union all select b.* from (select st.s_id,st.s_name,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id=sc.c_id and c.c_id="02" order by sc.s_score desc limit 0,2) b union all select c.* from (select st.s_id,st.s_name,c.c_name,sc.s_score from student st left join score sc on sc.s_id=st.s_id inner join course c on c.c_id=sc.c_id and c.c_id="03" order by sc.s_score desc limit 0,2) c   -- 借鉴(更准确,漂亮): select a.s_id,a.c_id,a.s_score from score a  where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 order by a.c_id 

43、统计每门课程的学生选修人数（超过5人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列

select sc.c_id,count(1) from score sc left join course c on c.c_id=sc.c_id group by c.c_id having count(1)>5 order by count(1) desc,sc.c_id asc 

44、检索至少选修两门课程的学生学号

select st.s_id from student st  left join score sc on sc.s_id=st.s_id group by st.s_id having count(1)>=2 

45、查询选修了全部课程的学生信息

select st.* from student st  left join score sc on sc.s_id=st.s_id group by st.s_id having count(1)=(select count(1) from course) 

46、查询各学生的年龄

select st.*,timestampdiff(year,st.s_birth,now()) from student st 

47、查询本周过生日的学生

 -- 此处可能有问题,week函数取的为当前年的第几周,2017-12-12是第50周而2018-12-12是第49周,可以取月份,day,星期几(%w), -- 再判断本周是否会持续到下一个月进行判断,太麻烦,不会写 select st.* from student st  where week(now())=week(date_format(st.s_birth,'%Y%m%d')) 

48、查询下周过生日的学生

select st.* from student st  where week(now())+1=week(date_format(st.s_birth,'%Y%m%d')) 

49、查询本月过生日的学生

select st.* from student st  where month(now())=month(date_format(st.s_birth,'%Y%m%d')) 

50、查询下月过生日的学生

 -- 注意:当 当前月为12时,用month(now())+1为13而不是1,可用timestampadd()函数或mod取模 select st.* from student st  where month(timestampadd(month,1,now()))=month(date_format(st.s_birth,'%Y%m%d')) -- 或 select st.* from student st where (month(now()) + 1) mod 12 = month(date_format(st.s_birth,'%Y%m%d')) 

5 参考资料 & 致谢

【1】数据库MySQL经典面试题之SQL语句
【2】sql语句练习50题(Mysql版)